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Grade 7-12 Math Review · Grade 7 · Quarter 2

Algebraic Expressions and Laws of Exponents

Only identical letter-parts can be added. Exponents have their own four rules.

Simplify

5x² + 3x − 2x² + 7x

Naming the parts.

7x² − 4x + 9 coefficient variable exponent constant
WordIn 7x² − 4x + 9
Terms7x², −4x and 9 — three of them
Coefficients7 and −4
Constant9, the term with no letter
Like termsnone here — every term differs

The sign in front belongs to the term. In 7x² − 4x the second term is −4x, not 4x, and that matters the moment you rearrange.

Like terms have identical letters and identical exponents.

Add the coefficients; the letter part does not change.

5x and 7x = 12x like ✓
5x² and 7x cannot combine different exponents ✗
3xy and 8yx = 11xy order does not matter ✓
4a and 4b cannot combine different letters ✗

Think of the letters as units. 5 metres + 7 metres is 12 metres; 5 square metres + 7 metres is simply two different measurements sitting side by side.

Evaluating: substitute with brackets.

Evaluate 3x² − 2x + 5 at x = −2

the task

3(−2)² − 2(−2) + 5

brackets around the value

= 3(4) + 4 + 5

(−2)² = 4, and −2 × −2 = +4

= 21

12 + 4 + 5

The brackets are not optional

Writing 3 × −2² gives −12, because only the 2 gets squared. Substituting a negative value always goes inside brackets.

The four exponent laws.

LawRuleExample
Productsame base, multiply → addx³ · x⁴ = x⁷
Quotientsame base, divide → subtractx⁸ ÷ x³ = x⁵
Powera power of a power → multiply(x³)⁴ = x¹²
Zeroanything (not 0) to the 0 → 1x⁰ = 1

Why x³ · x⁴ = x⁷: three x's times four x's is seven x's in a row. The rules are shortcuts for counting, not arbitrary.

(2x³)⁴

the power hits everything inside

= 2⁴ · x¹²

including the 2

= 16x¹²

not 2x¹²

(4a³)(3a⁶)

a product of two terms

= (4 × 3)(a³ · a⁶) = 12a⁹

numbers multiply, exponents add

Brackets, dividing terms, and negative exponents.

Distribute to every term, then collect like terms. Divide numbers with numbers and letters with letters.

Simplify −2(a − 6) + 3a.

−2a + 12 + 3a

−2 × a and −2 × (−6) = +12

= a + 12

−2a + 3a = a

The minus reaches the second term too

Writing −2(a − 6) as −2a − 12 multiplies the a by −2 but leaves the 6's sign alone, giving a − 12. A negative times a negative is positive, so the term is +12 and the answer is a + 12.

Simplify (18m⁶n²) ÷ (6m²n²).

18 ÷ 6 = 3

numbers with numbers

m⁶ ÷ m² = m⁴ and n² ÷ n² = n⁰ = 1

subtract the exponents for each letter

= 3m⁴

n has cancelled completely

What if the bigger exponent is underneath? Simplify y² ÷ y⁶.

y² ÷ y⁶ = y⁻⁴

2 − 6 = −4

= 1y⁴

a negative exponent means "one over"

Count it out: two y's on top, six underneath, so four y's are left on the bottom. A negative exponent is a reciprocal, never a negative number.

Variations: a fraction to substitute, a negative inside a power, and zero exponents.

The same rules; these are the values and signs that make them look new.

Evaluate 4x² − x when x = 12.

4(12)² − 12

substitute inside brackets

= 4(14) − 12 = 1 − 12

(12)² = 14

= 12

squaring a fraction below 1 makes it smaller

Fractions follow exactly the same order: exponent first, then multiply, then subtract.

Simplify (−2a²b)³.

(−2)³ · (a²)³ · b³

cube every factor inside

= −8a⁶b³

an odd power keeps the minus

The −2 is a factor like any other: it is cubed to −8, not left as −2 or turned into −6.

Simplify (5x)⁰ + 5x⁰.

(5x)⁰ = 1

the whole bracket is to the zero

5x⁰ = 5 × 1 = 5

only the x is to the zero

1 + 5 = 6

x has gone entirely

Brackets decide what the exponent touches, exactly as with (−2)² and −2².

The two mix-ups worth naming.

x³ · x⁴ = x⁷ add — multiplying
(x³)⁴ = x¹² multiply — a power of a power
x³ + x⁴ stays x³ + x⁴ not like terms at all
3x⁰ = 3(1) = 3 only the x is to the zero

The exponent laws apply to multiplying and dividing powers, never to adding them. x³ + x⁴ is already as simple as it gets.

Remember the flow

Identify like terms · Add their coefficients · Substitute inside brackets · Multiply exponents only for a power of a power

x² and x are as different as area and length. They never combine.

On the exam

Expect a "simplify" with several like terms or a bracket, an "evaluate at a negative value", and an exponent-law item that tests add versus multiply. The fastest route is to work one letter and one exponent at a time; the 10-second check is to put x = 2 into the question and into your answer and see that both give the same number.

Now you try

Practice problem

Simplify

(3a²b)³

Hint: three separate jobs inside the bracket — the number, the a and the b. Do each one, then put them back together.