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Grade 7-12 Math Review · Grade 9 · Quarter 1

Nature, Sum, and Product of Roots

One number under the root sign tells you what kind of answer to expect.

Describe the roots

What kind of roots does 2x² − 4x + 5 = 0 have?

The discriminant, and what each case looks like.

D = b² − 4ac

DRootsThe graph
positive, a perfect squaretwo rationalcrosses at two nice points
positive, not a perfect squaretwo irrationalcrosses at two awkward points
zeroreal and equal: one repeated roottouches the axis and turns
negativeno real roots (not real)never reaches the axis
D > 0 D = 0 D < 0

Worked, three times.

x² − 5x + 6 = 0 25 − 24 = 1 perfect square → two rational
x² − 6x + 9 = 0 36 − 36 = 0 one repeated root, x = 3
x² + 2x + 5 = 0 4 − 20 = −16 no real roots

Watch the sign of c

With c negative, −4ac becomes positive and the discriminant grows. x² + 2x − 5 has D = 4 + 20 = 24, a completely different case from x² + 2x + 5.

Forcing exactly one root.

Set the discriminant to zero and solve for the unknown.

4x² + kx + 9 = 0 has one root

find k

k² − 4(4)(9) = 0

D = 0

k² = 144

so k = ±12

Both values work: 4x² + 12x + 9 = (2x + 3)² and 4x² − 12x + 9 = (2x − 3)². Two answers is correct here, and giving only one is the usual slip.

Sum and product, without solving.

sum = −ba · product = ca

3x² − 12x + 7 = 0

a = 3, b = −12, c = 7

sum = 123 = 4

−ba, and −(−12) = 12

product = 73

ca

This is a fast way to check roots you have already found. If your two answers do not add to −ba, one of them is wrong.

Building an equation from its roots.

x² − (sum)x + (product) = 0

roots 5 and −2

write the equation

sum = 3, product = −10

add and multiply

x² − 3x − 10 = 0

note the minus before the sum

Check by factoring back: (x − 5)(x + 2) = x² − 3x − 10 ✓ The sum enters with a negative sign, which is where most errors come from.

Remember the flow

D = b² − 4ac · Positive, zero or negative · Perfect square? rational · Sum is −ba, product is ca

You can describe the roots completely without ever solving the equation.

Variations: k in the constant, a missing b, fraction roots.

The same three tools, used where the question is shaped differently.

The unknown is c: for what k does x² − 8x + k = 0 have equal roots?

(−8)² − 4(1)(k) = 0

D = 0

64 − 4k = 0

a straight line in k, not a square

k = 16

check: x² − 8x + 16 = (x − 4)² ✓

Only one answer this time: ± appears only when the unknown is the one being squared.

No x term: the sum and product of the roots of 2x² − 18 = 0

a = 2, b = 0, c = −18

the missing term means b = 0

sum = −02 = 0

−ba

product = −182 = −9

check: the roots are 3 and −3 ✓

With no x term the roots are opposites, so they always add to zero.

Fraction roots: write an equation with roots 12 and 3.

sum = 72, product = 32

add and multiply

x² − (72)x + 32 = 0

x² − (sum)x + product

2x² − 7x + 3 = 0

× 2 to clear the fractions

(2x − 1)(x − 3) = 0 ✓

factors back to the roots

Multiplying through by a whole number keeps the same roots and gives integer coefficients.

On the exam

Expect "describe the roots" from the discriminant, the sum or product of the roots of an equation whose a is not 1, a value of k that gives equal roots, and an equation built from two given roots. The fastest route is to write a, b and c with signs and never solve the equation: D for the kind, −ba and ca for sum and product. The 10-second check: factor or expand your built equation back to its roots, or test that a k value makes D exactly zero.

Now you try

Practice problem

Find the sum

What is the sum of the roots of 2x² + 9x − 5 = 0?

Hint: sum is −ba and product is ca. The minus belongs to the sum, not the product.