1
The discriminant, and what each case looks like.
D = b² − 4ac
| D | Roots | The graph |
| positive, a perfect square | two rational | crosses at two nice points |
| positive, not a perfect square | two irrational | crosses at two awkward points |
| zero | real and equal: one repeated root | touches the axis and turns |
| negative | no real roots (not real) | never reaches the axis |
2
Worked, three times.
x² − 5x + 6 = 0
25 − 24 = 1
perfect square → two rational
x² − 6x + 9 = 0
36 − 36 = 0
one repeated root, x = 3
x² + 2x + 5 = 0
4 − 20 = −16
no real roots
Watch the sign of c
With c negative, −4ac becomes positive and the discriminant grows.
x² + 2x − 5 has D = 4 + 20 = 24, a completely different case from x² + 2x + 5.
3
Forcing exactly one root.
Set the discriminant to zero and solve for the unknown.
4x² + kx + 9 = 0 has one root
find k
Both values work: 4x² + 12x + 9 = (2x + 3)² and 4x² − 12x + 9 = (2x − 3)². Two answers is
correct here, and giving only one is the usual slip.
4
Sum and product, without solving.
sum = −ba · product = ca
3x² − 12x + 7 = 0
a = 3, b = −12, c = 7
sum = 123 = 4
−ba, and −(−12) = 12
This is a fast way to check roots you have already found. If your two answers do not add to −ba, one of them is wrong.
5
Building an equation from its roots.
x² − (sum)x + (product) = 0
roots 5 and −2
write the equation
sum = 3, product = −10
add and multiply
x² − 3x − 10 = 0
note the minus before the sum
Check by factoring back: (x − 5)(x + 2) = x² − 3x − 10 ✓ The sum enters with a
negative sign, which is where most errors come from.
Remember the flow
D = b² − 4ac · Positive, zero or negative · Perfect square? rational · Sum is −ba, product is ca
You can describe the roots completely without ever solving the equation.
6
Variations: k in the constant, a missing b, fraction roots.
The same three tools, used where the question is shaped differently.
The unknown is c: for what k does x² − 8x + k = 0 have equal roots?
(−8)² − 4(1)(k) = 0
D = 0
64 − 4k = 0
a straight line in k, not a square
k = 16
check: x² − 8x + 16 = (x − 4)² ✓
Only one answer this time: ± appears only when the unknown is the one being squared.
No x term: the sum and product of the roots of 2x² − 18 = 0
a = 2, b = 0, c = −18
the missing term means b = 0
product = −182 = −9
check: the roots are 3 and −3 ✓
With no x term the roots are opposites, so they always add to zero.
Fraction roots: write an equation with roots 12 and 3.
sum = 72, product = 32
add and multiply
x² − (72)x + 32 = 0
x² − (sum)x + product
2x² − 7x + 3 = 0
× 2 to clear the fractions
(2x − 1)(x − 3) = 0 ✓
factors back to the roots
Multiplying through by a whole number keeps the same roots and gives integer coefficients.
On the exam
Expect "describe the roots" from the discriminant, the sum or product of the roots of an equation whose a is not 1, a value of k that gives equal roots, and an equation built from two given roots. The fastest route is to write a, b and c with signs and never solve the equation: D for the kind, −ba and ca for sum and product. The 10-second check: factor or expand your built equation back to its roots, or test that a k value makes D exactly zero.