The two quadrilaterals that are not parallelograms, and the shortcut that connects midpoints.
Find the median
A trapezoid has parallel sides of 14 cm and 22 cm. How long is its median (midsegment)?
The median is the average of the two parallel sides: 14 + 222 = 18 cm. C forgets to halve, and A subtracts. A sanity check settles it instantly — the median runs between the two sides, so its length must lie between 14 and 22.
1
A trapezoid has exactly one pair of parallel sides.
Part
Which sides
Bases
the two parallel ones
Legs
the two non-parallel ones
Median
joins the midpoints of the legs
"Exactly one pair" is what separates a trapezoid from a parallelogram. Two pairs of parallel sides would make it a parallelogram instead.
2
The median is the average of the bases.
m = b₁ + b₂2
bases 14 and 22
find the median
14 + 222 = 18
between the two ✓
median 15, one base 11
find the other base
11 + b2 = 15
set it up
b = 19
11 + b = 30
The area formula uses the same average: A = (b₁ + b₂)h2 is just median × height.
3
An isosceles trapezoid has equal legs.
Property
Detail
Legs equal
the definition
Base angles equal
the two at each base match
Diagonals equal
though they do not bisect each other
Opposite angles
supplementary
Equal, but not bisecting
The diagonals of an isosceles trapezoid are the same length, but
they do not cut each other in half. That last part is a parallelogram property,
and a trapezoid is not one.
4
A kite has two pairs of equal adjacent sides.
Sidestwo pairs, adjacent not oppositeunlike a parallelogram
Diagonalsperpendicularalways
One diagonalbisects the otheronly one, not both
Anglesone pair of opposite angles equalthe ones between unequal sides
Area of a kite = d₁ × d₂2, half the product of the diagonals — the same formula a
rhombus uses, since a rhombus is a kite with all four sides equal.
5
The midline theorem for triangles.
The segment joining two midpoints is parallel to the third side and half its length.
In triangle ABC, BC = 26
D and E are midpoints of AB and AC
DE = 26 ÷ 2 = 13
half the third side
DE is parallel to BC
and that comes free
This is the trapezoid median in miniature. A triangle is a trapezoid whose top base has shrunk to nothing, and 0 + 262 = 13 gives the same answer.
Remember the flow
Trapezoid median = average the bases · Isosceles → equal legs, base angles, diagonals · Kite → perpendicular diagonals · Midline = half the third side
A median must land between the two bases. If it does not, the arithmetic is wrong.
6
Bases described in words, and the angles along a leg.
When one base is described from the other, call the shorter one b and write the longer with b. Angles on the same leg lie between the parallel bases, so they add to 180°.
A trapezoid has a median of 15, and one base is 4 longer than the other. Find both bases.
bases b and b + 4
one letter for both
b + b + 42 = 15
the median is the average
2b + 4 = 30, so b = 13
double, then solve
bases 13 and 17
check: 13 + 172 = 15 ✓
Forgetting to average
Writing b + (b + 4) = 15 treats the median as the sum of the bases. It gives b = 5.5 and bases of 5.5 and 9.5 — whose median is only 7.5. The median is the sum divided by 2.
An isosceles trapezoid has a base angle of 70°. Find all four angles.
70° and 70°
base angles are equal
180° − 70° = 110°
same leg: supplementary
70°, 70°, 110°, 110°
check: total 360° ✓
7
Variations: a midline in x, a kite's equal angles, a height from the area.
The same facts, with the unknown moved to a new place.
D and E are midpoints of AB and AC; DE = x + 4 and BC = 3x − 2. Find BC.
2(x + 4) = 3x − 2
the third side is twice the midline
2x + 8 = 3x − 2, so x = 10
solve
BC = 3(10) − 2 = 28
check: DE = 14, half of 28 ✓
Double the midline, not the side: the "2" goes on the shorter segment.
In a kite, the angles where the equal sides meet are 110° and 50°. Find the other two.
360° − 110° − 50° = 200°
angles of a quadrilateral
200° ÷ 2 = 100° each
the remaining pair are equal
A kite has one pair of equal opposite angles — the two between the unequal sides.
A trapezoid has area 84 cm² and bases 9 cm and 15 cm. Find its height.
median = 9 + 152 = 12
area = median × height
12h = 84, so h = 7 cm
check: 12 × 7 = 84 ✓
Running the area formula backwards: divide the area by the median.
On the exam
Expect a trapezoid median from two bases or a base from the median, the midline of a triangle, a "which property belongs to which shape" item, and an angle along a leg of an isosceles trapezoid. The fastest route is the average — median = b₁ + b₂2, so double the median to get the sum of the bases — and the midline is half the third side. The 10-second check: a median must fall between the two bases, and the angles on one leg add to 180°.
Now you try
Practice problem
Find the base
A trapezoid has a median of 17 cm and one base of 12 cm. How long is the other base?
The median averages the bases: 12 + b2 = 17, so 12 + b = 34 and b = 22 cm. Check: 12 + 222 = 17 ✓ B subtracts and D forgets to subtract the 12 after doubling. Sanity check: the median of 17 sits between 12 and 22, as it must.
Hint: double the median first to get the sum of both bases, then
subtract the one you know.