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Grade 7-12 Math Review · Grade 9 · Quarter 3

Trapezoids, Kites, and the Midline Theorem

The two quadrilaterals that are not parallelograms, and the shortcut that connects midpoints.

Find the median

A trapezoid has parallel sides of 14 cm and 22 cm. How long is its median (midsegment)?

A trapezoid has exactly one pair of parallel sides.

22 (base) 14 (base) median 18 kite — diagonals perpendicular
PartWhich sides
Basesthe two parallel ones
Legsthe two non-parallel ones
Medianjoins the midpoints of the legs

"Exactly one pair" is what separates a trapezoid from a parallelogram. Two pairs of parallel sides would make it a parallelogram instead.

The median is the average of the bases.

m = b₁ + b₂2

bases 14 and 22

find the median

14 + 222 = 18

between the two ✓

median 15, one base 11

find the other base

11 + b2 = 15

set it up

b = 19

11 + b = 30

The area formula uses the same average: A = (b₁ + b₂)h2 is just median × height.

An isosceles trapezoid has equal legs.

PropertyDetail
Legs equalthe definition
Base angles equalthe two at each base match
Diagonals equalthough they do not bisect each other
Opposite anglessupplementary

Equal, but not bisecting

The diagonals of an isosceles trapezoid are the same length, but they do not cut each other in half. That last part is a parallelogram property, and a trapezoid is not one.

A kite has two pairs of equal adjacent sides.

Sides two pairs, adjacent not opposite unlike a parallelogram
Diagonals perpendicular always
One diagonal bisects the other only one, not both
Angles one pair of opposite angles equal the ones between unequal sides

Area of a kite = d₁ × d₂2, half the product of the diagonals — the same formula a rhombus uses, since a rhombus is a kite with all four sides equal.

The midline theorem for triangles.

The segment joining two midpoints is parallel to the third side and half its length.

In triangle ABC, BC = 26

D and E are midpoints of AB and AC

DE = 26 ÷ 2 = 13

half the third side

DE is parallel to BC

and that comes free

This is the trapezoid median in miniature. A triangle is a trapezoid whose top base has shrunk to nothing, and 0 + 262 = 13 gives the same answer.

Remember the flow

Trapezoid median = average the bases · Isosceles → equal legs, base angles, diagonals · Kite → perpendicular diagonals · Midline = half the third side

A median must land between the two bases. If it does not, the arithmetic is wrong.

Bases described in words, and the angles along a leg.

When one base is described from the other, call the shorter one b and write the longer with b. Angles on the same leg lie between the parallel bases, so they add to 180°.

A trapezoid has a median of 15, and one base is 4 longer than the other. Find both bases.

bases b and b + 4

one letter for both

b + b + 42 = 15

the median is the average

2b + 4 = 30, so b = 13

double, then solve

bases 13 and 17

check: 13 + 172 = 15 ✓

Forgetting to average

Writing b + (b + 4) = 15 treats the median as the sum of the bases. It gives b = 5.5 and bases of 5.5 and 9.5 — whose median is only 7.5. The median is the sum divided by 2.

An isosceles trapezoid has a base angle of 70°. Find all four angles.

70° and 70°

base angles are equal

180° − 70° = 110°

same leg: supplementary

70°, 70°, 110°, 110°

check: total 360° ✓

Variations: a midline in x, a kite's equal angles, a height from the area.

The same facts, with the unknown moved to a new place.

D and E are midpoints of AB and AC; DE = x + 4 and BC = 3x − 2. Find BC.

2(x + 4) = 3x − 2

the third side is twice the midline

2x + 8 = 3x − 2, so x = 10

solve

BC = 3(10) − 2 = 28

check: DE = 14, half of 28 ✓

Double the midline, not the side: the "2" goes on the shorter segment.

In a kite, the angles where the equal sides meet are 110° and 50°. Find the other two.

360° − 110° − 50° = 200°

angles of a quadrilateral

200° ÷ 2 = 100° each

the remaining pair are equal

A kite has one pair of equal opposite angles — the two between the unequal sides.

A trapezoid has area 84 cm² and bases 9 cm and 15 cm. Find its height.

median = 9 + 152 = 12

area = median × height

12h = 84, so h = 7 cm

check: 12 × 7 = 84 ✓

Running the area formula backwards: divide the area by the median.

On the exam

Expect a trapezoid median from two bases or a base from the median, the midline of a triangle, a "which property belongs to which shape" item, and an angle along a leg of an isosceles trapezoid. The fastest route is the average — median = b₁ + b₂2, so double the median to get the sum of the bases — and the midline is half the third side. The 10-second check: a median must fall between the two bases, and the angles on one leg add to 180°.

Now you try

Practice problem

Find the base

A trapezoid has a median of 17 cm and one base of 12 cm. How long is the other base?

Hint: double the median first to get the sum of both bases, then subtract the one you know.