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Grade 7-12 Math Review · Grade 11-12 · Gen Math: Business Math

Compounding More Than Once a Year

Divide the rate by the periods; multiply the years by them. Both, every time.

Find the amount

₱10,000 at 12% compounded quarterly for 2 years. What is it worth?

One adjustment, applied twice.

A = P(1 + rm)mt, where m is how many times a year.

annually m = 1 the plain formula
semi-annually m = 2 half the rate, twice the periods
quarterly / monthly m = 4m = 12 same rule, bigger m

Both changes or neither

Dividing the rate without multiplying the periods understates the answer; multiplying the periods without dividing the rate wildly overstates it. They are two halves of one adjustment and always travel together.

Work out rm and mt before anything else.

m = 2, r = 0.08, t = 3

name them first

rm = 0.04, mt = 6

4% per half-year, six of them

A = 50000(1.04)⁶

now it is the familiar formula

≈ ₱63,265.32

interest ₱13,265.32

Writing "4% for 6 periods" on its own line turns every one of these into the problem you already solved last lesson.

More often pays more, but not much more.

annually ₱12,544.00 10,000 at 12% for 2 years
quarterly ₱12,667.70 ₱123.70 more
monthly ₱12,697.35 only ₱29.65 more again

The gains shrink quickly. Going from yearly to quarterly is worth far more than going from quarterly to monthly, which is why banks rarely bother advertising the difference.

Compare offers with the effective annual rate.

8% quarterly: (1 + 0.084)⁴

one year's growth factor

= (1.02)⁴ ≈ 1.08243

effective rate 8.24%

8.2% annually: 1.082

effective rate 8.20%

8% quarterly wins

by about ₱4 per ₱10,000

The advertised, or nominal, rate is not comparable across different compounding frequencies. The effective annual rate is what puts two offers on the same footing.

Variations: money needed now, an effective rate on its own, quarters in months.

The principal is the unknown: deposit how much now, at 8% compounded quarterly, to have ₱50,000 in 3 years?

rm = 0.02, mt = 12

2% a quarter, twelve quarters

50000 = P(1.02)¹²

the familiar formula

P = 50000 ÷ 1.268242 ≈ ₱39,424.66

divide, do not subtract

The same two adjustments come first; only the last line runs backwards.

An effective rate on its own: 12% compounded monthly

(1 + 0.1212)¹² = (1.01)¹²

one year's growth factor

≈ 1.126825

multiply out

effective rate ≈ 12.68%

subtract 1, write as a percent

The effective rate is always a little above the nominal rate when m is more than 1, and equal to it when m = 1.

Quarters counted in months: ₱20,000 at 10% compounded quarterly for 9 months

rm = 0.104 = 0.025

2.5% a quarter

mt = 9 ÷ 3 = 3 quarters

a quarter is 3 months

A = 20000(1.025)³ ≈ ₱21,537.81

interest ₱1,537.81

Count the periods in the time given: 9 months is 3 quarters, not 9 periods and not 0.75.

A period that is not whole years still divides cleanly.

t = 15 months = 1.25 years

convert first

rm = 0.0612 = 0.005

0.5% a month

mt = 12 × 1.25 = 15

fifteen months, fifteen periods

A = 30000(1.005)¹⁵ ≈ ₱32,330.48

interest ₱2,330.48

₱12,667.70 for the opening problem

With monthly compounding the number of periods is simply the number of months, which is worth noticing: it saves converting to years and back for no reason.

On the exam

Periodical exams ask for the rate per period and the number of periods, then the amount or the interest; entrance tests compare two offers with different compounding, or slip in time given in months. Write rm and mt on their own line before anything else, then use A = P(1 + rm)mt. For a 10-second check, the answer must be a little more than the yearly-compounded amount for the same rate and time, never wildly more.

Remember the flow

Find m · rate per period rm · number of periods mt · A = P(1 + rm)mt

Divide the rate AND multiply the periods. One without the other is always wrong.
Now you try

Practice problem

Find the amount

₱8,000 at 10% compounded semi-annually for 3 years.

Hint: write "5% for 6 periods" down before reaching for the calculator. Everything after that is last lesson's formula.