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Grade 7-12 Math Review · Grade 11-12 · Gen Math: Logic

Conditionals and Valid Arguments

A valid argument can still have a false conclusion. Validity is about the shape, not the facts.

Judge the argument

"If it rains, the game is cancelled. The game was cancelled. Therefore it rained." Is this valid?

Three statements are built from every conditional.

converse q → p swapped
inverse ¬p → ¬q both negated
contrapositive ¬q → ¬p swapped AND negated

Only the contrapositive is guaranteed to match the original's truth. The converse and the inverse can each be false while the original is true.

One example shows why only one of them survives.

original: square → four sides

true

converse: four sides → square

FALSE: it could be a rectangle

inverse: not a square → not four sides

FALSE: a rectangle again

contrapositive: not four sides → not a square

true, as it must be

A single rectangle breaks both the converse and the inverse. That is no coincidence: the converse and the inverse are contrapositives of each other, so they always share a fate.

Two argument forms are always valid.

modus ponens p → q, p ⊢ q affirm the hypothesis
modus tollens p → q, ¬q ⊢ ¬p deny the conclusion
in words forwards from p, backwards from not-q both directions are safe

"If it rains the game is cancelled. It rained. So the game was cancelled." — modus ponens. "…The game went ahead. So it did not rain." — modus tollens. Both watertight.

Two near-misses are always invalid.

affirming the consequent p → q, q ⊢ p invalid ✗
denying the antecedent p → q, ¬p ⊢ ¬q invalid ✗
why they assume the converse which was never given

Both fallacies quietly swap in the converse

"If it rains the game is cancelled" does not say rain is the only reason for a cancellation. Reasoning from a cancellation back to rain relies on that extra claim — and it was never made.

Variations: denying the antecedent, a chain, an "or" with one side ruled out.

Denying the antecedent: "If a number ends in 0, it is divisible by 5. 35 does not end in 0. So 35 is not divisible by 5."

p: ends in 0, q: divisible by 5

name the parts

given p → q and ¬p, concluded ¬q

denying the antecedent

invalid: 35 = 5 × 7

a counterexample

The conditional says nothing about numbers that do not end in 0, so no conclusion about them follows.

A chain: "If I finish my homework, I watch TV. If I watch TV, I sleep late. So if I finish my homework, I sleep late."

p → q and q → r

p: homework, q: TV, r: sleep late

therefore p → r

the links join end to end

valid

a hypothetical syllogism

The middle statement q must be the conclusion of one premise and the hypothesis of the other; then it drops out.

An "or" with one side ruled out: "The answer is 12 or 15. It is not 12. So it is 15."

p ∨ q and ¬p

p: it is 12, q: it is 15

therefore q

the only option left

valid

a disjunctive syllogism

Ruling one side out forces the other. Knowing one side is TRUE, however, tells us nothing about the other, because "or" is inclusive.

Test the shape, then test with a counterexample.

p → q where p: divisible by 6, q: even

name the parts

given: p → q and q

affirming the consequent

invalid, and 14 proves it

even but not divisible by 6

The opening argument is invalid

Validity and truth are separate questions. An argument can be valid with a false conclusion, if a premise was false. And it can reach a true conclusion invalidly, by luck. Only validity is about the shape, and only the shape is what logic checks.

On the exam

Periodical exams ask for the converse, inverse or contrapositive of a statement, the name of an argument form, or whether a short argument is valid; entrance tests favour the two fallacies dressed in everyday words. Name p and q, write the argument in symbols, and match it to a form. For a 10-second check, look for one situation where every premise is true and the conclusion false — if you find one, the argument is invalid.

Remember the flow

Name p and q · Which form is it? · Ponens and tollens are valid · Affirming the consequent and denying the antecedent are not

Only the contrapositive is guaranteed to share the original's truth.
Now you try

Practice problem

Judge the argument

"If a student passes, she gets a certificate. Maria did not get a certificate. Therefore Maria did not pass." Is this valid?

Hint: write the conditional as p → q, then ask whether the second premise is p, q, ¬p or ¬q. Only p and ¬q lead anywhere.