Number the eight angles.
Four at the top crossing, four at the bottom one.
Say angle 1 is the 65° one.
The little arrowheads on the two horizontal lines are the standard mark for “these are parallel”. Without them, none of the rules below apply.
Eight angles, but only two different sizes.
Two parallel lines are cut by a transversal
One angle is 65°. How big is its co-interior partner?
Co-interior angles — same side of the transversal, between the parallels — are supplementary: 180 − 65 = 115°. D is the corresponding or alternate angle, which equals 65°. Only the same-side pair adds to 180.
Four at the top crossing, four at the bottom one.
Say angle 1 is the 65° one.
The little arrowheads on the two horizontal lines are the standard mark for “these are parallel”. Without them, none of the rules below apply.
across the X — equal
∠1 = ∠4 = 65°
side by side — add to 180°
∠2 = 180 − 65 = 115°
So the top crossing is 65, 115, 115, 65 — and that is already the whole story.
Because the lines are parallel, the bottom crossing is a copy of the top one.
| Pair name | Where they sit | Rule |
|---|---|---|
| corresponding | same corner, both crossings | equal |
| alternate interior | inside, opposite sides | equal |
| alternate exterior | outside, opposite sides | equal |
| co-interior | inside, same side | add to 180° |
Three of the four say “equal”. Only the same-side pair adds to 180°.
Names are worth knowing for exams, but the shortcut is simpler: every angle is either 65° or 115°, and nothing else is possible.
| Angle | Size | Why |
|---|---|---|
| ∠1 | 65° | given |
| ∠2 | 115° | linear pair with ∠1 |
| ∠3 | 115° | linear pair with ∠1 |
| ∠4 | 65° | vertical to ∠1 |
| ∠5 | 65° | corresponding to ∠1 |
| ∠6 | 115° | linear pair with ∠5 |
| ∠7 | 115° | linear pair with ∠5 |
| ∠8 | 65° | vertical to ∠5 |
65 + 115 = 180, so any two different-sized angles here are supplementary.
both acute, or both obtuse
they are equal
one acute, one obtuse
they add to 180°
Glance at the diagram, decide whether the two angles look the same or opposite, and you have the relationship without naming it.
Remove the arrowheads and every rule in Step 3 collapses. Vertical angles and linear pairs still hold — those never needed parallel lines.
p ∥ q. Alternate interior angles measure (7x − 18)° and (4x + 27)°. Find the angle.
7x − 18 = 4x + 27
alternate interior: equal
3x = 45, x = 15
− 4x, + 18, ÷ 3
7(15) − 18 = 87°
4(15) + 27 = 87 ✓
Different: x is not the angle. Both expressions must give the same number when we substitute.
p ∥ q. Co-interior (same-side) angles measure (3x + 14)° and (5x − 2)°. Find both.
(3x + 14) + (5x − 2) = 180
same side: total 180
8x + 12 = 180, x = 21
− 12, ÷ 8
77° and 103°
one acute, one obtuse ✓
Setting the co-interior pair equal gives 3x + 14 = 5x − 2, so x = 8 and both angles 38°. Two acute angles cannot sit on the same side between parallels — they would have to total 180.
A transversal crosses lines p and q. Co-interior angles measure 98° and 84°. Are p and q parallel?
98 + 84 = 182
add the same-side pair
182 ≠ 180
the rule fails
not parallel
extended far enough, they meet
Different: the rules run backwards too. Equal corresponding angles, or a same-side pair totalling exactly 180, prove the lines parallel; anything else proves they are not.
p ∥ q. One angle is 125°. Its linear-pair partner is (x + y)° and its corresponding angle is (x + 3y)°. Find x and y.
x + y = 55
linear pair: 180 − 125
x + 3y = 125
corresponding: equal
2y = 70, y = 35, x = 20
subtract the first from the second
Different: two unknowns need two equations — take one from each angle the figure ties to the 125°.
p ∥ q. A bent path runs from A on p to a point B between the lines, then to C on q. The angles at A and C are 35° and 50°. Find x, the angle at B.
dashed line through B, parallel to p and q
it splits x in two
upper part = 35°
alternate interior with A
lower part = 50°
alternate interior with C
x = 35 + 50 = 85°
add the two pieces
The rule “x = sum” needs the angles at A and C measured between the parallel line and the path, on the side the bend points to. If the figure gives the outside angle (here 145° instead of 35°), take 180 minus it first.
A triangle between the parallels. If A is on p and B, C are on q, the angles at A on either side of the triangle are alternate interior copies of ∠B and ∠C. All three angles at A lie on line p, so with ∠B = 55° and ∠C = 64° the angle of the triangle at A is 180 − 55 − 64 = 61°.
Expect the angles as expressions — set them equal (corresponding, alternate) or make them total 180 (same-side) — then a final step to a neighbouring angle, or a bend that needs the extra parallel line. Decide “equal or 180?” by the look: both acute or both obtuse means equal. Ten-second check: along one transversal every angle is one of only two sizes, and those two add to 180°.
Find x
One co-interior pair is (3x + 10)° and (2x − 5)°. Find x.
Co-interior angles total 180: (3x + 10) + (2x − 5) = 180 gives 5x + 5 = 180, so x = 35. The angles are 115° and 65°. ✓ A sets the two equal, which is the alternate-angle rule, not this one.