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UPCAT Math Review · Number sense

Significant Figures and Estimation

Which digits are carrying information — and how a rough answer protects you from a wrong one.

The problem

How many significant figures does 0.0450 have?

Every non-zero digit counts. Zeros depend on where they sit.

Kind of zeroCounts?Example
between digitsyes107 — 3 s.f.
leading, before any digitnever0.0045 — 2 s.f.
trailing, after a decimal pointyes2.50 — 3 s.f.
trailing, in a whole numberambiguous2500 — usually 2 s.f.
2500 2, 5 2 s.f. by convention
2.50 2, 5, 0 3 s.f.
0.0450 4, 5, 0 3 s.f.

Why a written zero can matter

2.5 says “somewhere between 2.45 and 2.55”. 2.50 claims more: between 2.495 and 2.505. The extra zero is a statement about how carefully the number was measured, which is why it counts.

Scientific notation removes the ambiguity.

WrittenSignificant figures
2.5 × 10³2
2.50 × 10³3
2.500 × 10³4 — all of them deliberate

All three equal 2500. Only the way they are written says how much of that is trustworthy — which is exactly what significant figures record.

Rounding to n figures: find the nth, then look right.

0.004073

the leading zeros are not figures

figures: 4, 0, 7, 3

the 4 is the first

2nd figure is 0; the next digit is 7

7 ≥ 5, so round up

= 0.0041

2 significant figures

Keep the place value

The answer is 0.0041, not 41 or 0.41. Rounding changes how precise a number is, never how big it is — so the zeros holding the decimal point in position all stay.

3847 to 2 s.f. 38|47 → down 3800, not 38
0.2996 to 3 s.f. 299|6 → up 0.300 — keep the zeros
7.0499 to 3 s.f. 7.04|99 → look at one digit only 7.05

An answer cannot be more precise than its inputs.

OperationMatch theExample
× and ÷fewest significant figures4.5 × 2.13 = 9.585 → 9.6
+ and −fewest decimal places12.5 + 3.42 = 15.92 → 15.9

Measuring a room as 4.5 m by 2.13 m and reporting 9.585 m² claims millimetre accuracy you never had. Two figures in, two figures out.

Round at the end, not at every step. Rounding partway and then continuing lets small errors compound — carry the extra digits and cut them once.

Variations: a subtraction that loses figures, an exact count, and a round-up that rolls over.

Close numbers subtracted: 15.38 m − 15.2 m.

15.38 − 15.2 = 0.18

the raw difference

fewest decimal places: 1 (from 15.2)

+ and − follow decimal places

= 0.2 m

only 1 significant figure is left

What is different: both inputs have 3 or 4 figures, yet the answer has 1. Subtracting near-equal measurements wipes out figures.

An exact count: 6 identical boxes each weigh 2.35 kg. Report the total.

6 × 2.35 = 14.1

the 6 is counted, not measured

= 14.1 kg

3 s.f., from 2.35 alone

What is different: a count of whole objects is exact and does not limit the answer. Treating 6 as one figure gives 10 kg and throws away a good measurement.

A round-up that rolls over: 99.96 to 3 significant figures.

99.9|6

third figure is the 9 in the tenths

6 ≥ 5, so 99.9 → 100.0

every 9 rolls over

= 1.00 × 10²

“100” alone would read as 1 s.f.

What is different: the carry adds a digit, so the figures shift one place left. Scientific notation is the clean way to show all three.

One-figure estimates catch the big mistakes.

48.7 × 21.3

the real calculation

≈ 50 × 20

round each to 1 s.f.

= 1000

the size of the answer

exact: 1037.31

about 3.7% away — close enough to check with

2 s.f. · 3 s.f. · 3 s.f. · 0.0041 · about 1000

What an estimate is for

Not for choosing between 1037 and 1039 — for spotting 103.7 or 10 373. Decimal point errors and dropped zeros are the expensive mistakes, and a five-second estimate finds every one of them.

On the exam

Expect rounding to n significant figures (leading zeros never count, and the place value must stay), “which has exactly three”, and a measured product or sum reported to the right precision. Multiply or divide → fewest significant figures; add or subtract → fewest decimal places. Decide the rule before you calculate.

Check: does the rounded answer still mean the same thing?

0.0041 vs 0.004073 same size, 2 figures ✓
9.6 vs 9.585 2 figures, as the inputs allow ✓
1037.31 estimate said ~1000 right order of magnitude ✓

Remember the flow

Count from the first non-zero digit · Round once, at the end · Estimate to check the size

Leading zeros never count; trailing zeros after a point always do.
Now you try

Practice problem

The problem

Round 27 486 to 2 significant figures.