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UPCAT Math Review · Geometry

Similar Figures: k, k², k³

Scale a shape by k and its lengths grow by k, its areas by k², its volumes by k³. One exponent per dimension — that single sentence solves the whole topic.

The problem

Two similar solids have sides in the ratio 2 : 3. The smaller has volume 24 cm³. What is the larger's volume?

Why the exponents: count the dimensions.

side 1 side 2 side 1 side 2 area × 2² = 4 volume × 2³ = 8

Double a square's side and it holds 2 × 2 = four of the originals — each dimension doubles independently. A cube doubles into 2 × 2 × 2 = eight. Length is one factor of k, area two, volume three. Nothing to memorise once you see the tiling.

The three-row table that answers everything.

QuantityScales byAt k = 32
length, perimeterk× 32
area, surface areak²× 94
volumek³× 278

V = 24 · 278 = 81 cm³

the worked answer

Backwards questions: un-square or un-cube first.

areas 9 : 16 → k = √916 = 3 : 4

root the area ratio to get the side ratio

then volumes = 3³ : 4³ = 27 : 64

side ratio first, then re-raise

Never jump area-ratio → volume-ratio directly. The side ratio k is the bridge every crossing goes through.

Spot it in disguise.

"A photo is enlarged 150%…", "a model car is built at 1 : 24…", "the map scale is 1 cm : 5 km…" — all similar-figure questions. Enlarging a photo 150% multiplies ink AREA by 1.5² = 2.25; a 1 : 24 model holds 124³ of the real car's volume. The words change; k, k², k³ does not.

Prices work the same way when they follow area. A 25 cm pizza costs ₱500; a 15 cm one at the same price per unit of area costs 500 × (1525)² = 500 × 925 = ₱180 — not 500 × 1525 = ₱300, which scales by length alone.

Variations: a percent increase, an area that doubles, a map area.

Every length of a solid is increased by 20%. By what percent do its surface area and its volume increase?

k = 1.2

100% + 20%

area × 1.2² = × 1.44

up 44%

volume × 1.2³ = × 1.728

up 72.8%

Percents do not multiply by 2 and 3

“Area up 40%, volume up 60%” doubles and triples the 20%. The factor is 1.2, and it is the factor that gets squared or cubed; subtract 1 only at the end.

A square of side 6 cm is enlarged so that its area doubles. Find the new side.

k² = 2, so k = √2

un-square the area factor

side = 6√2 cm ≈ 8.49 cm

not 12 cm

Different: the area factor is not a perfect square, so k is irrational. Doubling the side would make the area 4 times as big.

On a map, 1 cm stands for 0.5 km. A park covers 6 cm² of the map. Find its real area.

1 cm² stands for 0.5 × 0.5 = 0.25 km²

square the length scale

6 × 0.25 = 1.5 km²

not 6 × 0.5 = 3

Different: the scale is given as a length with units. A map area uses the scale squared, units included.

From volume down to area, and the half-full cone.

Two similar solids have volumes in the ratio 27 : 125. The smaller has surface area 36 cm². Find the surface area of the larger. Cube-root down to k, then square back up.

k = 3√27125 = 35

volume ratio → side ratio

areas in the ratio 3² : 5² = 9 : 25

side ratio → area ratio

36 × 259 = 100 cm²

smaller to larger

Applying the volume ratio to an area

36 × 12527 ≈ 166.7 uses the volume factor on an area. Any time the given ratio and the asked quantity have different dimensions, go through k.

A cone-shaped glass, point down, is filled to two thirds of its height. What fraction of the glass holds water? The water is itself a cone, similar to the glass.

k = 23

height of water ÷ height of glass

volume fraction = (23)³ = 827

under a third, even at two thirds’ height

This only works with the point at the bottom. Upside down, the air at the top is the similar cone, and the water is 1 − (air fraction).

On the exam

Expect a ratio given in one dimension and asked in another — areas to lengths, volumes to areas — or a story: a model, a photo enlargement, a pizza priced by area, a cone part-filled. Find k first, then raise it to the power the question needs. Ten-second check: lengths change least, volumes most.

Check with a concrete cube.

side 2 cube V = 8 scale by 32 → side 3
side 3 cube V = 27 = 8 × 278 exactly k³ ✓

Remember the flow

Lengths × k · Areas × k² · Volumes × k³ · Backwards? Root down to k first

One exponent per dimension.
Now you try

Practice problem

The problem

Two similar triangles have sides in the ratio 2 : 5. The smaller has area 8. What is the larger's area?