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UPCAT Math Review · Percentages

Successive Discounts

20% then 10% is not 30% off — the second cut is smaller than it looks.

The problem

A shirt priced at ₱500 is discounted by 20%. The sale price is then discounted by a further 10%. What is the final price?

Turn each discount into what you KEEP.

Paying is easier to track than saving.

you pay 80% 20% off the whole bar is the original price

20% off

keep 0.80

10% off

keep 0.90

100% − 20% = 80%

Why not just subtract?

Subtracting works too, but it takes two steps each time. Multiplying by what you keep does it in one.

Apply the first discount.

₱400 ₱100 80% of the ₱500 bar stays, 20% is cut away

0.20 · 500 = 100

the saving

500 − 100 = 400

what you actually pay

or in one move

0.80 · 500 = 400

₱400

this is the SALE price, not the final one

The second 10% comes off the SALE price.

correct

10% of 400 = 40

wrong

10% of 500 = 50

that price is gone

₱500 ₱400 ₱360 start the second cut starts here after both

Each discount acts on whatever the price is at that moment. Discounts never stack onto the original.

Take 10% off the sale price.

₱360 ₱400 sale price 90% of the sale price stays

0.10 · 400 = 40

the second saving

400 − 40 = 360

the final price

or in one move

0.90 · 400 = 360

₱360 final price

Chain the multipliers into one.

Skip the middle price entirely.

500 · 0.80 · 0.90 = 360

original · keep 80% · keep 90%

0.80 · 0.90 = 0.72

you pay 72%, so the real saving is 28%

if you add them

30% off » ₱350

the truth

28% off » ₱360

The missing 2% is the 10% that was never charged on the ₱100 you already saved.

Backwards: from the final price to the original.

After successive discounts of 25% and 10%, a jacket sells for ₱2,025. What was the original price?

0.75 × 0.90 = 0.675

the buyer pays 67.5% of the original

0.675 × P = 2,025

the final price is a part of P

P = 2,025 ÷ 0.675 = ₱3,000

divide, never add percents back

Adding 35% back uses the wrong base

2,025 × 1.35 ≈ ₱2,734 — the discounts were taken from the original, so putting them back on the smaller final price undershoots. Check forwards instead: 3,000 × 0.75 = 2,250, then 2,250 × 0.90 = 2,025 ✓.

Variations: three discounts with an awkward percent, and a rise then a fall.

Three discounts, one of them 12.5%. A ₱4,800 tablet gets successive discounts of 20%, 12.5% and 5%. Find the final price and the single equivalent discount.

keep: 0.80 × 0.875 × 0.95

12.5% off keeps 87.5%

0.80 × 0.875 = 0.70; 0.70 × 0.95 = 0.665

pair the easy ones first

4,800 × 0.665 = ₱3,192

the final price

1 − 0.665 = 33.5% off

not 20 + 12.5 + 5 = 37.5%

What is different: three factors and a decimal percent. The chain just gets one link longer.

Up first, then down by the same percent. A price is raised 25%, then the new price is cut 25%. What is the net change?

1.25 × 0.75 = 0.9375

a rise keeps 125%

1 − 0.9375 = 0.0625

below where it started

a 6.25% decrease

on ₱800: 1,000, then 750

What is different: one multiplier is above 1. The cut is taken from the bigger, raised price, so the two changes do not cancel.

“No change” is the trap

+25% and −25% look like they cancel, but 25% of ₱1,000 is more than 25% of ₱800. Doing the cut first and the rise second gives the same 0.9375 — order never matters, only the multipliers.

An unknown second discount.

Successive discounts of 25% and x% equal a single discount of 40%. Find x.

0.75 × (keep) = 0.60

a 40% discount keeps 60%

keep = 0.60 ÷ 0.75 = 0.80

the second multiplier

x = 20

keeping 80% is 20% off

40 − 25 = 15 is the trap answer. The same multipliers handle a markup first: marked 25% above cost, then 10% and 10% off, sells at 1.25 × 0.9 × 0.9 = 1.0125 of cost — a profit of just 1.25%.

On the exam

Every successive-discount item is one product of multipliers: final = original × keep₁ × keep₂. Forward questions multiply; “original price” questions divide; an unknown discount is the missing factor. The 10-second check: your answer's single equivalent discount must be a little less than the two percents added.

Check: rebuild the two savings.

first saving 20% of 500 = 100 500 becomes 400
second saving 10% of 400 = 40 400 becomes 360
total saved 100 + 40 = 140 140 out of 500

140 ÷ 500 = 0.28 » 28% off

and 500 − 140 = 360

Remember the flow

Keep, not cut · Chain · Multiply

Percents multiply, they never add.
Now you try

Practice problem

Practice problem

A jacket priced at ₱800 is discounted by 25%. The sale price is then increased by 10% for tax. What is the final price?

Hint: one goes down and one goes up. An increase means you keep more than 100%, so its multiplier is bigger than 1.