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Grade 7-12 Math Review · Grade 11-12 · Precalculus: Analytic Geometry

The Parabola

Every point on it is the same distance from one point and one line.

Find the focus

x² = 12y

A focus, a line, and equal distances.

directrix focus vertex P d d

That equal-distance rule is the definition. Everything else — the formulas, the shape, the reflector property — is a consequence of it.

The squared variable says which way it opens.

x² = 4cy opens up if c > 0 focus (0, c), directrix y = −c
x² = −4cy opens down focus (0, −c)
y² = 4cx opens right focus (c, 0), directrix x = −c

x squared opens vertically, y squared opens sideways

It feels backwards at first. The trick is to ask which variable is free to take any value: in x² = 4cy, y can be anything positive, so the curve runs upward. The focus always sits on the axis the curve opens along.

Match the form, then read everything off.

y² = −20x matches y² = −4cx

y squared, so it opens sideways

4c = 20, so c = 5

always divide by 4

negative, so it opens LEFT

focus (−5, 0)

directrix x = 5

on the far side of the vertex

The focus is always inside the curve and the directrix always outside, the same distance the other way, so focus and directrix sit 2c apart (here 5 + 5 = 10). If your two answers end up on the same side, a sign has gone astray.

A shifted vertex works exactly like a shifted circle.

(x − h)² = 4c(y − k)

the general form

(x − 4)² = 12(y + 2)

h = 4, k = −2

vertex (4, −2), 4c = 12 so c = 3

opens upward

focus (4, 1), directrix y = −5

3 up and 3 down from the vertex

Find the vertex first, then step c units along the axis of symmetry for the focus and c units the other way for the directrix. Everything is measured from the vertex.

Variations: working backwards, a fractional c, and a general form.

Three versions of the same reading-off, each with one new wrinkle.

Backwards: the focus is (0, −3) and the directrix is y = 3. Find the equation.

vertex (0, 0)

halfway between focus and directrix

focus below the vertex, so it opens DOWN

c = 3

x² = −12y

4c = 12, with the minus for down

Here we build the equation from the picture. Sketching the focus and the line first settles the sign.

A fractional c: y² = 6x

4c = 6, so c = 64 = 32

divide by 4, even when it is not whole

focus (32, 0), directrix x = −32

opens right

latus rectum = 4c = 6

the coefficient itself

Nothing changes when c is a fraction. Keep it as 32; a rounded 1 or 2 puts the focus in the wrong place.

A general form: x² + 6x − 4y + 1 = 0

x² + 6x = 4y − 1

keep the x terms on the left

x² + 6x + 9 = 4y + 8

add 9 to both sides

(x + 3)² = 4(y + 2)

factor the 4 out of the right side

vertex (−3, −2), c = 1, focus (−3, −1)

directrix y = −3

Factor the coefficient out of the right side before reading k; 4y + 8 hides k = −2.

The latus rectum sets the width, and the shape does the work.

latus rectum length 4c the chord through the focus
large c wide, shallow curve focus far from the vertex
small c narrow, steep curve focus close to the vertex

Focus (0, 3) for the opening problem

Every ray coming in parallel to the axis bounces off a parabola straight through the focus. That is why satellite dishes, car headlamps and solar cookers are all parabolic — and why the focus has its name.

Remember the flow

Which variable is squared? · Divide the other coefficient by 4 to get c · Step c from the vertex for the focus · Step c the other way for the directrix

Focus inside the curve, directrix outside, always the same distance.

On the exam

Tests give an equation and ask for the focus, directrix, vertex or the way it opens, or give the focus and directrix and ask for the equation. The fastest route: see which variable is squared, divide the other coefficient by 4 to get c, and step c from the vertex. A 10-second check: the vertex must sit exactly halfway between the focus and the directrix.

Now you try

Practice problem

Find the focus and directrix

y² = 16x

Hint: y is squared, so the curve opens along the x-axis. Divide 16 by 4, not by 2.