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Grade 7-12 Math Review · Grade 11-12 · Precalculus: Trigonometry

Sum and Difference Identities

cos(A + B) is not cos A + cos B. It never was, and the formula says why.

Choose the expansion

cos(A + B)

Sine keeps the sign; cosine flips it.

sin(A ± B) = sin A cos B ± cos A sin B same sign
cos(A ± B) = cos A cos B ∓ sin A sin B OPPOSITE sign
tan(A ± B) = tan A ± tan B1 ∓ tan A tan B both signs appear

The cosine sign is the one that catches everyone

cos(A + B) has a minus and cos(A − B) has a plus. Every other formula keeps the sign you were given. Check the cosine one against a known value before trusting it: cos(90° + 0°) should give 0, and cos 90 cos 0 − sin 90 sin 0 = 0 ✓ The same test kills the tempting shortcut cos(A + B) = cos A + cos B: with A = B = 45°, cos 90° = 0, but cos 45° + cos 45° = √2. One known angle is enough to expose a wrong formula.

Sine and cosine mix; they do not stay separate.

sin(A + B) both terms mix sin and cos sin·cos + cos·sin
cos(A + B) terms stay pure cos·cos − sin·sin
the memory hook "sine mixes, cosine matches" and cosine flips the sign

Getting the pattern of the terms right is half the work; getting the sign right is the other half. Both are worth a ten-second check with a known angle.

Build an awkward angle from two familiar ones.

105° = 60° + 45°

both are special angles

cos(60 + 45) = cos60 cos45 − sin60 sin45

plus inside, MINUS in the formula

= (12)(√22) − (√32)(√22)

substitute the known values

= √2 − √64

about −0.259 ✓

Check the size: 105° is just past 90°, so its cosine should be small and negative. An answer of −0.259 passes; a positive answer means the cosine sign was not flipped. Any sum or difference of 30°, 45°, 60° and 90° works the same way: 75° = 45° + 30°, and 15° = 45° − 30°, so cos 15° = cos 45° cos 30° + sin 45° sin 30°.

Running the formula backwards is the real skill.

sin80 cos50 − cos80 sin50

matches sin A cos B − cos A sin B

= sin(80 − 50)

A = 80, B = 50

= sin 30° = 12

an exact value from two that are not

Four unpleasant values collapse into one exact answer. Spotting the pattern in a long expression is worth far more marks than expanding one, and exam questions know it.

The cosine pattern backwards: the sign between the terms decides.

"cos·cos" and "sin·sin" side by side is a cosine formula. The sign between them tells us whether the angles add or subtract, the opposite way round.

Simplify cos 50° cos 20° + sin 50° sin 20°.

cos50 cos20 + sin50 sin20

pure terms: a cosine formula

PLUS between the terms, so it is cos(A − B)

cosine flips the sign

= cos(50 − 20) = cos 30°

A = 50, B = 20

= √32

an exact value

Adding the angles because the sign is plus

Reading the + as "add" gives cos 70°, which is not a special angle at all — a sign that the pattern was misread. For cosine, + between the terms means subtract the angles, and − means add them.

Variations: a quadrant II angle, tangent, and radians.

The same formulas, with a negative piece, a fraction to tidy, and π in place of degrees.

A quadrant II angle: sin A = 513 (A in II), cos B = 35 (B in I). Find cos(A − B).

cos A = −1213, sin B = 45

cosine is negative in II

cos(A − B) = cos A cos B + sin A sin B

minus inside, plus outside

= (−1213)(35) + (513)(45) = −3665 + 2065

substitute

= −1665

a negative answer is fine

Using +1213 gives 5665. The quadrant sign has to be fixed before substituting.

Tangent: tan 75° = tan(45° + 30°)

= 1 + √331 − √33

tan 45 = 1, tan 30 = √33

= 3 + √33 − √3

multiply top and bottom by 3

= 9 + 6√3 + 39 − 3 = 12 + 6√36

multiply by 3 + √3 top and bottom

= 2 + √3

about 3.73 ✓

Check: 75° is steep, so its tangent should be well above 1.

Radians: sin(π12) = sin(π3 − π4)

= sin(π3)cos(π4) − cos(π3)sin(π4)

sine keeps the minus

= (√32)(√22) − (12)(√22)

π3 is 60°, π4 is 45°

= √6 − √24

about 0.259

π12 is 15°, so its sine should be small and positive. It is.

You usually have to find the missing pieces first.

sin A = 817 → cos A = 1517

8-15-17 triangle, quadrant I

cos B = 45 → sin B = 35

3-4-5 triangle

sin(A+B) = (817)(45) + (1517)(35)

sin mixes, sign unchanged

= 3285 + 4585 = 7785

just under 1, which is plausible

cos(A + B) = cos A cos B − sin A sin B

The quadrant matters: in quadrant I both missing values are positive, but in quadrant II cos A would have been −1517 and the answer would change completely. Always use the Pythagorean identity for the size and the quadrant for the sign.

Remember the flow

Sine mixes and keeps the sign · Cosine matches and flips it · Split awkward angles into special ones · Watch for the pattern in reverse

Test any formula you are unsure of against a known angle before using it.

On the exam

Tests ask for an exact value such as cos 75° or sin 15°, for a long expression to be collapsed back into one function, or for sin(A + B) given two ratios and quadrants. The fastest route: sine mixes and keeps the sign, cosine matches and flips it; split the angle into 30°, 45°, 60° pieces, or read A and B straight off the pattern. A 10-second check: estimate the angle's sine or cosine on the unit circle and see the exact answer has the right size and sign.

Now you try

Practice problem

Simplify

cos 70° cos 10° + sin 70° sin 10°

Hint: the terms are cos·cos and sin·sin, so this is a cosine formula. Now check the sign between them to decide whether the angles add or subtract.