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SAT Math Review · Problem-Solving and Data Analysis

Reading histograms, dot plots and box plots

Each display throws something away to show you something else. Knowing what is missing is half the question.

The histogram shows the distribution of the times, in minutes, that each of 45 callers spent on hold. The first bar represents times of at least 0 minutes but less than 4 minutes, and so on.

Hold times of 45 callers 024 6810 121416 048 121620 Time on hold (minutes) Number of callers

Which of the following can be determined from the histogram?

Three displays, three different bargains.

Every display trades detail for shape. Ask what it kept and what it threw away, and most questions answer themselves.

DisplayShowsHides
dot plotevery individual value, one dot eachnothing — but it is unreadable past about 40 values
histogramhow many values fell in each intervalthe individual values inside a bar
box plotthe five-number summary and the spreadthe mean, the counts, and the shape within each quarter
dot plot → every value survives histogram → only the interval survives box plot → only five numbers survive

Read that middle column from the top down and you are losing information at every step. That is not a flaw: a dot plot of 2,000 salaries is a smear, while a box plot of the same 2,000 tells you in one glance where the middle half sits.

A histogram bar is a count, and the count is all you get.

The height of a bar, read off the vertical axis, is how many values landed in that interval. Here is the opening histogram with the five counts written on.

Hold times of 45 callers 614 128 5 024 6810 121416 048 121620 Time on hold (minutes) Number of callers

6 + 14 + 12 + 8 + 5 = 45

the bar heights add to the whole group

less than 8 minutes → 6 + 14 = 20 callers

two whole bars, so the count is exact

at least 12 minutes → 8 + 5 = 13 callers

the last two bars, again exact

less than 6 minutes → cannot be found

6 cuts a bar in half, and the bar does not say where its 14 values sit

The boundary belongs to the bar on its right

“At least 4 but less than 8” is the standard SAT wording, so a caller who waited exactly 8 minutes is counted in the third bar, not the second. That is why “less than 8” is a clean 20 and “8 or less” is not answerable. Whenever a cut-off falls on a boundary between two bars you can count; whenever it falls inside a bar you cannot.

A dot plot keeps every value, so you can count anything.

One dot is one member of the data set. Nothing has been grouped, so no question about the values is out of reach.

Servings of vegetables, 18 students at least 4 → 5 students 012 345 6 Number of servings

n = 1 + 3 + 5 + 4 + 3 + 1 + 1 = 18

count the dots, never the tick marks

at least 4 → 3 + 1 + 1 = 5 students

the value 4 itself is included

fewer than 2 → 1 + 3 = 4 students

“fewer than 2” stops before the 2s

median: 9th and 10th of 18 → (2 + 3) ÷ 2 = 2.5

a histogram could never give you this

“At least”, “more than”, “fewer than”, “at most”

These four words decide whether the dots sitting on the cut-off are in or out, and an SAT choice list almost always contains the answer you get by reading the wrong one. “At least 4” and “at most 4” both include the three dots sitting at 4; “more than 4” and “fewer than 4” both exclude them. Underline the phrase before you start counting.

A box plot is five numbers, and each section holds a quarter of the data.

Minimum, Q1, median, Q3, maximum. The box runs from Q1 to Q3, so the box holds the middle 50% of the values.

Ages of 24 running club members Q1 25Q3 44 minimum 16median 32maximum 68 25%25% 25%25% the box holds the middle 50% 102030 405060 70 Age (years)

range = 68 − 16 = 52 years

the two whisker ends

IQR = 44 − 25 = 19 years

the two box edges — the width of the middle half

24 members ÷ 4 = 6 per section

about 6 under 25, about 12 inside the box

A long whisker is spread, not a crowd

The right whisker here covers 24 years and the left one only 9, but both hold about six members. The long whisker means those six are strung out from 44 to 68, not that there are more of them. And notice what is absent: the plot never shows the mean, never shows how many members there are unless the stem says so, and never shows whether the ages inside the box are bunched at 26 or at 43.

Running totals find the median interval; nothing finds the mean.

The hardest histogram items ask where the middle value sits. Add the bars left to right until you pass the middle position.

Interval (minutes)CallersRunning total
0 to 466
4 to 81420
8 to 121232
12 to 16840
16 to 20545

n = 45, so the median is the 23rd value

(45 + 1) ÷ 2 = 23

the running total reaches 20, then 32

position 23 lands in the third bar

median is between 8 and 12 minutes

the interval is the answer; the exact value is gone

The mean cannot be pinned down at all, but it can be trapped. Push every value to the bottom of its interval, then to the top, and the true mean must lie between the two results.

low: (0·6 + 4·14 + 8·12 + 12·8 + 16·5) ÷ 45 = 328 ÷ 45 ≈ 7.3

everybody at the left edge of their bar

high: (4·6 + 8·14 + 12·12 + 16·8 + 20·5) ÷ 45 = 508 ÷ 45 ≈ 11.3

everybody at the right edge

so 7.3 < mean < 11.3 minutes

enough to rule out a choice of 5 or 15

“Must be true” versus “could be true”

This is the difference the hard items live on. “The median is less than 12” must be true, because position 23 is fixed by counting. “The mean is less than 10” only could be true, since the mean is anywhere from about 7.3 to 11.3. When a statement about a histogram depends on where values sit inside a bar, it can never be forced.

Pick the display that answers the question you were asked.

Some items hand you the question and ask which display would settle it. Match the question to the thing the display kept.

The questionDot plotHistogramBox plot
How many values equal 7?yesnono
How many values are between 10 and 20?yesyes, if 10 and 20 are bar edgesno
What is the exact mean?yesnono
What is the median?yes, exactlythe interval onlyyes, exactly
What is the IQR?yes, with worknoyes, at a glance
Which of two groups is more spread out?yesyesyes, and fastest

Two rows are worth memorising. Only the dot plot gives an exact mean. Only the box plot gives an IQR without counting.

Where the calculator earns its keep

Desmos will build the display for you if a stem hands you a raw list. Paste the values into a Desmos table, then plot histogram(L, 4), dotplot(L) or boxplot(L) to see the same data three ways. It is a good way to build the instinct for what each one hides — on the test itself the display is already drawn, and the work is reading it.

Check: does the display actually contain the answer?

the total 6 + 14 + 12 + 8 + 5 = 45 bar heights match the stated group size ✓
the cut-off “less than 8” sits on a bar edge so the count is exact ✓
the dot plot 18 dots, median 2.5 every value survived, so anything is countable ✓
the box plot 16 ≤ 25 ≤ 32 ≤ 44 ≤ 68 five numbers in order, four equal quarters ✓

Remember the flow

What did the display keep? · Count whole bars or whole stacks · Quarters, not crowds

If the question needs a value the display threw away, the answer is “cannot be determined”.
Now you try

Practice problem

The box plot summarizes the weights, in pounds, of the 40 dogs at an animal shelter.

Weights of 40 dogs 01020 304050 607080 Weight (pounds)

Based on the box plot, which of the following statements is true?

Hint: go through the four choices asking one question of each — is this something a box plot keeps? Three of them ask for information that was thrown away when the 40 weights were reduced to five numbers.